Out riggers would work, but they are heavy and a lot of work to build. I think that if I have stability issues with the trailer I'll probably look at using tie downs that drill in to the sand (I forget what they are called).
But back to my original question:
If the guy wires are attached 18' up and 6' out, the leverage of the tower should triple the force applied to the guy wire, right? So 450 lbs. Now the force will actually originate 3' above the 18' mark so it will be somewhat larger than 150 lbs at the 18' mark.
WARNING: Math problem ahead!
Given:
Lateral load of 150 lbs at top of 21' tower,
Guy wires attached 18' up and 6' out.
- lbs * 21' / 18' = 175lbs of lateral load at the point where the guy wires attach.
- ' / 6' = 3 (leverage presented by tower/guy wire geometry)
- lbs * 3 = 525 lbs (tension on guy wire)
Would this be the correct way to figure out the stress on the cable?
If my formula is correct it should be fine with the 1540 lb cable.
This assumes that the stress will be directly opposite the shortest guy wire. What if the lateral load is between 2 guy wires? How would the stress be figured out then?
Would I draw an imaginary line between the two guy wire anchors opposite the force and measure the distance from the tower base, in the direction that the force was coming from, to that imaginary line? Then use that measurement for the base leg of the triangle to compute the leverage that the tower would have on the cables?
Then how would the force be distributed between the 2 guy wires? Would it be proportional to the relative distance, from the point that the force vector crossed the imaginary line, to the 2 anchors at either end of the imaginary line?
So I have a 2 part math problem and I'm not sure if I'm setting it up right. Since this is a computation that should probably be performed on any home made tower, I hope someone here will know if I am doing it right.
Thanks,
Eric